(1/3)^2x=1/9

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Solution for (1/3)^2x=1/9 equation: 



(1/3)^2x=1/9

We move all terms to the left:

(1/3)^2x-(1/9)=0



Domain of the equation: 3)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)^2x-(+1/9)=0

We get rid of parentheses

(+1/3)^2x-1/9=0

We calculate fractions


()/3^2x*9)+(-3x)/3^2x*9)=0

We calculate fractions

We do not support expression: x^6

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